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MEP 803 loaded up

CapePrep

Active member
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Location
MA
I am sure this has been discussed 100 times+, but This is the first time I have had a chance to really load up my recent frankenstein machine(took 2 bad ones and made 1 good one!). This thing is amazing. 62amps per leg. That is 14.9KW. I did run it at 125%ish for probably 30-40min and then it tripped the overload. I had 2 4500 watt heaters and an old double wall oven set to all 4 elements cranking. In the second video you can see me adding the space heaters and the engine barely notices it. Love these things!
https://www.youtube.com/watch?v=hCEIL4G9u8A
https://www.youtube.com/watch?v=2jbyJXfT-m4
 

Hard Head

Member
Steel Soldiers Supporter
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Greenville SC
Were you running 240 single phase? Then 62 amps is 11.904 KW This is an excellent output on a 12 KVA (10KW) generator head since it can take it for a long time without overheating. You just forgot to include the power factor in your calculations. Sorry I am just an engineer that has had this crap engraved in his brain for over 40 years now. It is kind of like fingernails on a chalk board to me since I am an EE. Sorry not trying to say anything bad OK! Please don't take take this as me being a smart as*. I am enjoy helping others as others have helped me. I check out this site as much as I can since as I always learn something.


KW

AC single phase amps to kilowatts calculations
The power P in kilowatts (kW) is equal to the power factor PF times the phase current I in amps (A), times the RMS voltage V in volts (V) divided by 1000:
P(kW) = PF × I(A) × V(V) / 1000 = (.8 x 62 x 240) / 1000 = 11.904KW

AC three phase amps to kilowatts calculation
Calculation with line to line voltage
The power P in kilowatts (kW) is equal to square root of 3 times the power factor PF times the phase current I in amps (A), times the line to line RMS voltage VL-L in volts (V) divided by 1000:

P(kW) = √3 × PF × I(A) × VL-L (V) / 1000

Calculation with line to neutral voltage
The power P in kilowatts (kW) is equal to 3 times the power factor PF times the phase current I in amps (A), times the line to neutral RMS voltage VL-N in volts (V) divided by 1000:

P(kW) = 3 × PF × I(A) × VL-N (V) / 1000


_______________________________________________________________________________________

KVA


How to convert electric current in amps (A) to apparent power in kilovolt-amps (kVA). You can calculate kilovolt-amps from amps and volts, but you can't convert amps to kilovolt-amps since kilovolt-amps and amps units do not measure the same quantity.

Single phase amps to kVA calculation formula
The apparent power S in kilovolt-amps is equal to phase current I in amps, times the RMS voltage V in volts, divided by 1000:
S(kVA) = I(A) × V(V) / 1000
So kilovolt-amps are equal to amps times volts divided by 1000. kilovolt-amps = amps × volts / 1000orkVA = A ⋅ V / 1000
Example:
What is the apparent power in kVA when the phase current is 12A and the RMS voltage supply is 110V?
Solution: S = 12A × 110V / 1000 = 1.32kVA

3 phase amps to kVA calculation formula
Calculation with line to line voltage The apparent power S in kilovolt-amps (with balanced loads) is equal to square root of 3 times the phase current I in amps, times the line to line RMS voltage VL-L in volts, divided by 1000:
S(kVA) = √3 × I(A) × VL-L(V) / 1000

So kilovolt-amps are equal to √3 times amps times volts divided by 1000. kilovolt-amps = √3 × amps × volts / 1000 or kVA = √3 × A ⋅ V / 1000

Example:
What is the apparent power in kVA when the phase current is 12A and the line to line RMS voltage supply is 190V?
Solution:
S = √3 × 12A × 190V / 1000 = 3.949kVA

Calculation with line to neutral voltage
The apparent power S in kilovolt-amps (with balanced loads) is equal to 3 times the phase current I in amps, times the line to neutral RMS voltage VL-N in volts, divided by 1000:
S(kVA) = 3 × I(A) × VL-N(V) / 1000
So kilovolt-amps are equal to 3 times amps times volts divided by 1000. kilovolt-amps = 3 × amps × volts / 1000orkVA = 3 × A ⋅ V / 1000

Example
What is the apparent power in kVA when the phase current is 12A and the line to neutral RMS voltage supply is 120V?
Solution:
S = 3 × 12A × 120V / 1000 = 4.32kVA
 
Last edited:

jamawieb

Well-known member
1,437
556
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Location
Ripley/TN
I test all my units with a 14kw commercial load bank for at least 6 hours. I've found that 14kw is the max with a per resistance load as with my load bank. Anything over 14kw trips the breaker.
 

CapePrep

Active member
266
195
43
Location
MA
HH, Wow that was great! I had no idea about all of that. I was using basic OHM's law, and obviously forgot a few parts ! Thanks for the schoolin'
Were you running 240 single phase? Then 62 amps is 11.904 KW This is an excellent output on a 12 KVA (10KW) generator head since it can take it for a long time without overheating. You just forgot to include the power factor in your calculations. Sorry I am just an engineer that has had this crap engraved in his brain for over 40 years now. It is kind of like fingernails on a chalk board to me since I am an EE. Sorry not trying to say anything bad OK! Please don't take take this as me being a smart as*. I am enjoy helping others as others have helped me. I check out this site as much as I can since as I always learn something.


KW

AC single phase amps to kilowatts calculations
The power P in kilowatts (kW) is equal to the power factor PF times the phase current I in amps (A), times the RMS voltage V in volts (V) divided by 1000:
P(kW) = PF × I(A) × V(V) / 1000 = (.8 x 62 x 240) / 1000 = 11.904KW

AC three phase amps to kilowatts calculation
Calculation with line to line voltage
The power P in kilowatts (kW) is equal to square root of 3 times the power factor PF times the phase current I in amps (A), times the line to line RMS voltage VL-L in volts (V) divided by 1000:

P(kW) = √3 × PF × I(A) × VL-L (V) / 1000

Calculation with line to neutral voltage
The power P in kilowatts (kW) is equal to 3 times the power factor PF times the phase current I in amps (A), times the line to neutral RMS voltage VL-N in volts (V) divided by 1000:

P(kW) = 3 × PF × I(A) × VL-N (V) / 1000


_______________________________________________________________________________________

KVA


How to convert electric current in amps (A) to apparent power in kilovolt-amps (kVA). You can calculate kilovolt-amps from amps and volts, but you can't convert amps to kilovolt-amps since kilovolt-amps and amps units do not measure the same quantity.

Single phase amps to kVA calculation formula
The apparent power S in kilovolt-amps is equal to phase current I in amps, times the RMS voltage V in volts, divided by 1000:
S(kVA) = I(A) × V(V) / 1000
So kilovolt-amps are equal to amps times volts divided by 1000. kilovolt-amps = amps × volts / 1000orkVA = A ⋅ V / 1000
Example:
What is the apparent power in kVA when the phase current is 12A and the RMS voltage supply is 110V?
Solution: S = 12A × 110V / 1000 = 1.32kVA

3 phase amps to kVA calculation formula
Calculation with line to line voltage The apparent power S in kilovolt-amps (with balanced loads) is equal to square root of 3 times the phase current I in amps, times the line to line RMS voltage VL-L in volts, divided by 1000:
S(kVA) = √3 × I(A) × VL-L(V) / 1000

So kilovolt-amps are equal to √3 times amps times volts divided by 1000. kilovolt-amps = √3 × amps × volts / 1000 or kVA = √3 × A ⋅ V / 1000

Example:
What is the apparent power in kVA when the phase current is 12A and the line to line RMS voltage supply is 190V?
Solution:
S = √3 × 12A × 190V / 1000 = 3.949kVA

Calculation with line to neutral voltage
The apparent power S in kilovolt-amps (with balanced loads) is equal to 3 times the phase current I in amps, times the line to neutral RMS voltage VL-N in volts, divided by 1000:
S(kVA) = 3 × I(A) × VL-N(V) / 1000
So kilovolt-amps are equal to 3 times amps times volts divided by 1000. kilovolt-amps = 3 × amps × volts / 1000orkVA = 3 × A ⋅ V / 1000

Example
What is the apparent power in kVA when the phase current is 12A and the line to neutral RMS voltage supply is 120V?
Solution:
S = 3 × 12A × 120V / 1000 = 4.32kVA
 
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