The following is the math to find the ratio:
The computed loaded radius of a 9.00x20 tire is 19.44 inches; that of an 8.25x20 is 17.55 inches (not 18.46" as in my previous post - not sure what happened there, sorry).
If the rear ratio in the IH were the same as the White, what would the front ratio need to be and still run 9.00x20 tires on the front?
Loaded diameter of 9.00x20 / Sprocket Pitch Diameter = Front Ratio / Rear Ratio
2*19.44 / 22.918 = ? / 4.44 or ? = 4.44*2*19.44 / 22.918 = 7.533.
The ratio of 7.53 to 1 is not possible with any single reduction ring / pinion ratio. I computed ratios with a range of pinion tooth count from 4 to 12, against a ring gear tooth count of 10 to 60. The closest ratio is 45 tooth ring gear, 6 tooth pinion, or 7.50:1.
Why not use 7.50:1? The error between 7.53:1 and 7.50:1 is 0.44%. Sounds pretty small why not go for it?
The circumference of a 9.00x20 tire is 2*pi*r = 122.14 inches. That is how far the HT travels in one full rotation of the front tire. 0.44% of that is about 1/2". Or, with a ratio of 7.50:1 instead of 7.53:1 in the front differential with the White rear ratio of 4.44:1, the front tire or the tracks must slip/skid 0.5" for every full single revolution of the front tire. That might not seem so bad, but expanding on this, the front tire must slip one full revolution for every 1/2 mile that the vehicle moves forward, assuming the tracks don't slip at all. When put into that context, this rate of mismatch would lead to unacceptable tire and/or track wear when the front axle is engaged.