Two 12V batteries connected in series yeilds 24V. As we all know and have experienced in our Deuces. Now lets say you tap off one of these batteries to run a 12V load. In simple terms lets say the load on the one battery used to power the 12V load is now really reading 10.5 volts because you ran it too long. Now instead of having a 24 volt system to the deuce when you go to start it, you only have a 22.5 volt system. While this may not seem like a big deal, you need to look at it in terms of ohms law I=E/R where current (I), is determined by the supply voltage (22.5V)/(resistance of the starter motor) Just for grins, lets say the resistance of the motor .5 ohms. The most juice the battery could supply is 45 amps at the given resistance.
Lets take the case of two equalized batteries healthy and at 12 volts each. This in series is 24V. Again using Ohms law of I=E/R Current(I) = 24v(e)/.5 ohms(R). With a healthy battery set up with each battery measuring 12Volts gives 48 amps.
It may not seem like much, and there are many other aspects to consider like heat, cold, internal resistance and so forth, but I wanted to show you mathmatically why this makes a difference. In reality, the internal resistance of the winding motor on the starter may be a lot lower (short circuit) with would make for a larger delta in the numbers.
I used .5 as the example because it makes the math easy.
Tommy