If you're going to custom mod a dual master cylinder setup, why stop there? Heck, make it a 3 master cylinder setup. Run extra hard lines to the rear-rear if needed. That way you don't have to worry about proportioning valves at all. And you would have triple redundant brakes.
Just install a pivot system on the brake pedal to negate the "hair trigger" effect from pumping 3x the fluid for the same pedal push.
Or you could run your two master cylinder kit into left & right instead of front/back. Sure it's goofy. But in an emergency it would work. Well, it would work if you have tons of upper body strength to keep the thing on the road. That also would not require any proportioning.
I kind of like the triple master cylinder idea though.
I have no idea how all the air assist stuff works. I'm planning to read up on it real soon. But surely you could tee off the air lines & put a larger air tank on?
What you propose won't work unless you are a gorilla!
Some simple hydraulics needs to be discussed:
First, PSI, or pounds per square inch, tells a large part of the story of how hydraulics works. Hydraulic systems are effectively a variation on the lever.
Some examples contrived to have simple numbers:
1) A system with one master cylinder (MC), and one wheel cylinder (WC):
If the MC piston is 1 square inch area, and the WC piston is 2 square inchs area, 20 lbs of force from the WC piston will require 10 lbs of force on the MC piston. The MC's piston will have to move twice as far as the WC's piston.
2) A system with one master cylinder (MC), and two wheel cylinders (WC):
If the MC piston is 1 square inch area, and the WC pistons are 2 square inches area each, 20 lbs of force from each WC piston will require 10 lbs of force on the MC's piston, but the MC's piston will have to move 2 times the distance each WC piston has to move, or twice as far as the MC in example #1. [This is a 1 axle system.]
3) A system with one master cylinder (MC) and four wheel cylinders (WC):
If the MC piston is 1 square inch area, and the WC pistons are each 2 square inches area, 20 lbs of force from each of the four WC pistons will require 10 lbs of force on the MC's piston, but the MC's piston will have to move 2 times the distance each WC piston has to move, or four times as far as the MC in example #1. [This is a 2 axle system, like a normal car. A 3 axle system works the same, but multiplies by 3.]
And finally, the two master cylinder example:
4) A split system with two separate systems each the same as in example #2, will need twice the force to move both MC pistons as in example #2, but the MC piston will move half as far as the MC piston in example #3.
And a three master cylinder example:
5) A split system with three separate systems, each the same as in example #2, will need three times the force to move the three MC pistons as in example #2.
Please note that each wheel cylinder will need to provide the same amount of force, to the brake shoes, to stop the deuce regardless of the MC configuration.
If you use two normal deuce master cylinders in your redundant system, you will double the force at the brake pedal needed to stop the deuce. If you use 3 normal deuce master cylinders in your redundant system, you will triple the force at the brake pedal needed to stop the deuce...
Basically, your redundancy will make it physically impossible for you to apply enough pedal force to stop your deuce if the air assist quits. Even if the air assist is working, your redundancy will multiply the brake pedal force by the number of redundant MC's.
The only way to make a split circuit system work would be to use a MC that has two pistons, each with 1/2 the area of the original, but traveling twice as far.
-Chuck